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2^m+1=(2^4)^m+7
We move all terms to the left:
2^m+1-((2^4)^m+7)=0
We get rid of parentheses
2^m-2^4^m-7+1=0
We add all the numbers together, and all the variables
2^m-2^4^m-6=0
We move all terms containing m to the left, all other terms to the right
2^m-2^4^m=6
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